In: Physics
Event 1: Front of train enters tunnel.
Event 2: Front of train exits tunnel.
Event 3: End of train enters tunnel.
Event 4: End of train exits tunnel.
a.
Event 1: (0,0)
Event 2: Time taken by train to exit the tunnel will be
so, coordinates will be(12 c µs,20µs)
Event 3
Since the length of the train and tunnel is same in O's IRF. so, these two event occur at the same time but different x.
coordinates(0,20µs)
Event 4
It will take additional 20µs for back of the train to exit the tunnel. so, coordinates are (12 c.µs, 40µs).
b) Original length of the train:
length in O's frame =Original length/gamma
Now, in train's frame the track is moving so length of track
c) Lorentz transfornations are
Event 1: (0,0)
Event 2 (x,t)=(12 c µs,20µs)
Event 3: (x,t)= (0,20µs)
Event 4 (x,t) (12 c.µs, 40µs)
d) Two events simultaneous in tunnel's frame are event 2 and event 3 but these events are not simultaneous in train's frame. time elapsed=6µs
e) It depends upon the frame, for tunnel's frame it fits. For, trains frame it does not when everything is in rest train does not fit inside the tunnel.