Question

In: Physics

Ice with a mass of 52 g originally at 0.0 deg. C is added to 450...

Ice with a mass of 52 g originally at 0.0 deg. C is added to 450 g of water originally at 80. deg. C. Determine the final temperature once all the ice melts and all the water reaches thermal equilibrium. Assume that no heat is exchanged with the container.

Solutions

Expert Solution

Mass of the ice is

Heat required to melt ice at 0oC to water at 0oC is

Heat required to change the temperature of a substance of mass m from Ti to Tf is

Let Tf be the final temperature. Heat required to increase the temperature of water from 0oC to Tf is

The heat is supplied by the water of mass M=450g which is initially at temperature 80oC. The heat supplied by the water is

It is given that no heat is exchanged with the container.

Substituting m=52g, M=450g C=4.186 J/(goC)


Related Solutions

What is the minimum mass of ice at 0.0 C that must be added to 1...
What is the minimum mass of ice at 0.0 C that must be added to 1 kg of water to cool the water from 28 C to 12 C? (heat of fusion = 333 J/g, Specific heat capacity of ice = 2.06 J/g K, water = 4.184J/g K)
What is the entropy change when 5.20 g of ice at 0.0°C are added to 250...
What is the entropy change when 5.20 g of ice at 0.0°C are added to 250 mL of water in an insulated thermos at 30.0°C? answer in (J/K)
What is the entropy change when 5.20 g of ice at 0.0°C are added to 250...
What is the entropy change when 5.20 g of ice at 0.0°C are added to 250 mL of water in an insulated thermos at 30.0°C? answer in (J/K)
Ice of mass 45.5 g at -10.5° C is added to 208 g of water at...
Ice of mass 45.5 g at -10.5° C is added to 208 g of water at 15.8° C in a 101 g glass container of specific heat 0.200 cal/g-°C at an initial temperature of 27.5° C. Find the final temperature of the system.
A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in...
A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C. What is the final equilibrium temperature? (Specific heat for aluminum is 900 J/kg×°C, the specific heat of water is 4 186 J/kg×°C, and Lf = 3.33 ´ 105 J/kg.)
A mixture containing 21.4g of ice (at 0.0 degrees C) and 75.3 g of water (55.3...
A mixture containing 21.4g of ice (at 0.0 degrees C) and 75.3 g of water (55.3 degrees C) is placed in an insulated container. Assuming no loss of heat to the surroundings, what is the final temp of the mixture ?
A 70.0 g ice cube at 0.0 degrees C is placed in a lake whose temperature...
A 70.0 g ice cube at 0.0 degrees C is placed in a lake whose temperature is 18.0 degrees C. Calculate the change in entropy (in joules/Kelvin) of the system as the ice cube comes to thermal equilibrium with the lake. (c for water = 4186 J/kg-K)
Ice (mass=26.9 g) with an initial temperature of -15.8 oC is added to 181.4 g of...
Ice (mass=26.9 g) with an initial temperature of -15.8 oC is added to 181.4 g of water at 27.2oC in an isolated calorimeter. The mass of the aluminum calorimeter cup and stirrer together is 51.6 g. Using the values for specific heat and the nominal value of Lfice given in your laboratory manual, determine temperature of the system when it reaches equillibrium (Tf).
A 40-g block of ice is cooled to −72°C and is then added to 590 g...
A 40-g block of ice is cooled to −72°C and is then added to 590 g of water in an 80-g copper calorimeter at a temperature of 26°C. Determine the final temperature of the system consisting of the ice, water, and calorimeter. (If not all the ice melts, determine how much ice is left.) Remember that the ice must first warm to 0°C, melt, and then continue warming as water. (The specific heat of ice is 0.500 cal/g · °C...
A 31 g block of ice is cooled to −66◦C. It is added to 577 g...
A 31 g block of ice is cooled to −66◦C. It is added to 577 g of water in an 84 g copper calorimeter at a temperature of 29◦C. Find the final temperature. The specific heat of copper is 387 J/kg ·◦C and of ice is 2090 J/kg ·◦C . The latent heat of fusion of water is 3.33 × 105 J/kg and its specific heat is4186J/kg·◦C. Answer in units of ◦C.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT