Question

In: Statistics and Probability

Insurance companies are interested in knowing the population percent of drivers who always buckle up before...

Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 399 drivers and find that 283 claim to always buckle up. Construct a 90% confidence interval for the population proportion that claim to always buckle up.

Solutions

Expert Solution

Z for 90% confidence interval = Z0.05 = 1.645

p = 283 / 399 =0.7093

Confidence interval

                               

                               

                                = (0.6719 , 0.7467)

orchestra answered 2 years ago
Next > < Previous

Related Solutions

Insurance companies are interested in knowing the population percent of drivers who always buckle up before...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 404 drivers and find that 301 claim to always buckle up. Construct a 91 % confidence interval for the population proportion that claim to always buckle up. Use interval notation, for example, [1,5]
Insurance companies are interested in knowing the population percent of drivers who always buckle up before...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly surveyed 400 drivers and found that 320 claimed they always buckle up. What is the sample statistic and what is its distribution? Include the parameters of this distribution. Construct a 97% confidence interval the population percent of drivers who always buckle up before riding in a car. Interpret the above confidence interval What is the minimum number you...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 415 drivers and find that 286 claim to always buckle up. Construct a Invalid variable% confidence interval for the population proportion that claim to always buckle up. Use interval notation, for example, [1,5]
Insurance companies are interested in knowing the population percent of drivers who always buckle up before...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 415 drivers and find that 286 claim to always buckle up. Construct a 95% confidence interval for the population proportion that claim to always buckle up. Use interval notation, for example, [1,5]
Insurance companies are interested in knowing the population percent of drivers who always buckle up before...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 401 drivers and find that 319 claim to always buckle up. Construct a 92% confidence interval for the population proportion that claim to always buckle up.
Insurance companies are interested in knowing the population percent of drivers who always buckle up before...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 387 drivers and find that 287 claim to always buckle up. Construct a 91 % confidence interval for the population proportion that claim to always buckle up. Use interval notation, for example, [1,5] ___________
Insurance companies are interested in knowing the population percent of drivers who always buckle up before...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 382 drivers and find that 283 claim to always buckle up. Construct a 85% confidence interval for the population proportion that claim to always buckle up. Use interval notation, for example, [1,5]
Insurance companies are interested in knowing the population percent of drivers who always buckle up before...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. a) When designing a study to determine this population proportion, what is the minimum number of drivers you would need to survey to be 95% confident that the population proportion is estimated to within 0.02? (Round your answer up to the nearest whole number.) _______ drivers b) If it was later determined that it was important to be more than...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 410 drivers and find that 282 claim to always buckle up. Construct a 95% confidence interval for the population proportion that claim to always buckle up.
Insurance companies are interested in knowing the population percent of drivers who always buckle up before...
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 410 drivers and find that 283 claim to always buckle up. Construct a 91% confidence interval for the population proportion that claim to always buckle up.
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT