Question

In: Physics

Rubidium-strontium dating. The rubidium isotope 8737Rb, a β emitter with a half-life of 4.75×1010yr, is used...

Rubidium-strontium dating. The rubidium isotope 8737Rb, a β emitter with a half-life of 4.75×1010yr, is used to determine the age of rocks and fossils. Rocks containing fossils of ancient animals contain a ratio of 8738Sr to 8737Rb of 0.0310.

Assuming that there was no 8738Sr3887Sr present when the rocks were formed, estimate the age of these fossils.

Solutions

Expert Solution

Radioactive decay of into is given below

+

Half life is 4.75 1010 years

Ratio of to found in the fossils of ancient animal = 0.031

Hence fraction of undecayed atoms = 0.969

Hence from radioactive decay equation, we get

where T is half-life period of

ln(0.969) = [ -ln2 t ] / ( 4.75 1010 )

Hence age of rocks and fossil, t = - [ ln(0.969) / ln(2) ] ( 4.75 1010 ) year

t = 2.158 1010 year


Related Solutions

Rubidium-87 decays by β production to strontium-87 with a half life of 4.7 × 1010 years....
Rubidium-87 decays by β production to strontium-87 with a half life of 4.7 × 1010 years. What is the age of a rock sample that contains 105.9 µg 87Rb and 7.9 µg 87Sr ? ____ years old Assume that no 87Sr was present when the rock was formed. The atomic masses are given in the table below: Nuclide Atomic Mass 87Rb 86.90919 87Sr 86.90888
Rubidium-87 decays by β production to strontium-87 with a half life of 4.7 × 1010 years....
Rubidium-87 decays by β production to strontium-87 with a half life of 4.7 × 1010 years. What is the age of a rock sample that contains 104.6 µg 87Rb and 7.1 µg 87Sr ? Assume that no 87Sr was present when the rock was formed. The atomic masses are given below: Nuclide Atomic Mass 87Rb 86.90919 87Sr 86.90888
he isotope 81Thallium204 has a half-life of 3.78 years and can be used as a nanotechnology...
he isotope 81Thallium204 has a half-life of 3.78 years and can be used as a nanotechnology MEMS (Micro Electric Mechanical System) power source device. It decays through beta emission into 82Pb204 with a branching ratio of 97.1 percent with an average decay energy of 0.764 MeV. It also decays through electron capture to 80Hg204 with a branching ratio of 2.9 percent with a decay energy of 0.347 MeV. Calculate the energy release per decay event in [MeV/disintegration] Calculate its total...
The half-life of a radioactive isotope represents the average time it would take half of a...
The half-life of a radioactive isotope represents the average time it would take half of a collection of this type of nucleus to decay. For example, you start with a sample of 1000 Oxygen-15 (15O) nuclei, which has a half-life of 122 seconds. After 122 seconds, half of the 15O nuclei will have decayed into Nitrogen-15 (15N) nuclei. After another 122s, half of the remaining Oxygen nuclei will have also decayed, and so on. Suppose you start with 3.71×10315O nuclei...
The half-life of 235U, an alpha emitter, is 7.1×108 yr. Part A Calculate the number of...
The half-life of 235U, an alpha emitter, is 7.1×108 yr. Part A Calculate the number of alpha particles emitted by 4.4 mg of this nuclide in 2 minutes. Express your answer using two significant figures.
Suppose a patient is given 140 mg of I−131, a beta emitter with a half-life of...
Suppose a patient is given 140 mg of I−131, a beta emitter with a half-life of 8.0 days.Assuming that none of the I−131 is eliminated from the person's body in the first 4.0 hours of treatment, what is the exposure (in Ci) during those first four hours? (please I need the correct answer with steps *no predictions )
Polonium-218 is an alpha emitter with a half-life of 3.0 minutes. **)If a sample contains 55...
Polonium-218 is an alpha emitter with a half-life of 3.0 minutes. **)If a sample contains 55 mg of Po−218 (atomic mass = 218.008965 amu), how many alpha emissions would occur in 27.0 minutes? **)If the polonium were ingested by a person, to what dose of radiation (in Ci) would the person be exposed? (I need correct answer for this please)
Strontium 38Sr90 has a half-life of 29.1 yr. It is chemically similar to calcium, enters the...
Strontium 38Sr90 has a half-life of 29.1 yr. It is chemically similar to calcium, enters the body through the food chain, and collects in the bones. Consequently, 38Sr90 is a particularly serious health hazard. How long (in years) will it take for 99.9488% of the 38Sr90 released in a nuclear reactor accident to disappear?
The half-life of a certain radioactive isotope is 3.24 years. If a sample consisting of 6.023x1023...
The half-life of a certain radioactive isotope is 3.24 years. If a sample consisting of 6.023x1023 atoms were allowed to decay, what percentage of the original number of atoms have decayed after 2.0 years? A) 50 B) 46 C) 32 D) 54 E) 60
The half life of an isotope is 20 minutes. After 2.00 hours, 0.10 grams of the...
The half life of an isotope is 20 minutes. After 2.00 hours, 0.10 grams of the sample remains. how many grams was in the original sample.?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT