Question

In: Statistics and Probability

Do a traditional oneway analysis of variance to see if the pulse before running depends on...

Do a traditional oneway analysis of variance to see if the pulse before running depends on activity level. State conclusion in a jargon-free sentence, check assumptions and conditions. Report any problems and discuss how they impact interpretation of the result.

PuBefore PuAfter Ran? Smokes? Sex Height Weight ActivityL
48 54 no yes male 68 150 1
54 56 no yes male 69 145 2
54 50 no no male 69 160 2
58 70 yes no male 72 145 2
58 58 no no male 66 135 3
58 56 no no female 67 125 2
60 76 yes no male 71 170 3
60 62 no no male 71 155 2
60 70 no yes male 71.5 164 2
60 66 no no female 62 120 2
61 70 no no female 65.5 120 2
62 76 yes yes male 73.5 160 3
62 75 yes no male 72 195 2
62 58 yes no male 72 175 3
62 100 yes no female 66 120 2
62 98 yes yes female 62.75 112 2
62 62 no no male 74 190 1
62 66 no no male 70 155 2
62 68 no yes male 73 155 2
62 66 no no female 65 122 3
64 88 yes no male 66 140 2
64 80 yes no male 69 155 2
64 62 no no male 75 160 3
64 60 no no female 66 130 3
66 78 yes yes male 73 190 1
66 82 yes yes male 69 175 2
66 102 yes no male 70 130 2
66 72 no no female 66 125 2
66 76 no no female 65 115 2
68 72 yes no male 74 190 2
68 76 yes no male 67 145 2
68 76 yes yes male 74 180 2
68 112 yes no female 70 125 2
68 66 no yes male 67 150 2
68 68 no no male 71 150 3
68 64 no no male 69.5 150 3
68 68 no no male 72 142 3
68 66 no no male 68 155 2
68 68 no no female 69 150 2
68 68 no no female 62 110 2
70 72 yes yes male 73 170 3
70 106 yes no male 71 170 2
70 94 yes yes male 75 185 2
70 62 no yes male 66 130 2
70 70 no no male 70 150 2
70 66 no yes male 75 190 2
72 80 yes no male 66 135 3
72 74 no yes male 69 170 2
72 74 no yes male 68 155 3
72 70 no no male 71 140 2
72 70 no no female 63 118 2
72 68 no no female 68 110 2
74 84 yes no male 73 165 1
74 76 yes no male 70 157 2
74 70 no no male 73 155 3
74 74 no no male 73 155 2
74 76 no no male 67 123 2
76 118 yes no male 71 138 2
76 76 no no male 72 215 2
76 76 no no male 74 148 3
76 76 no yes female 62 108 3
76 76 no no female 61.75 108 2
78 104 yes yes female 68 130 2
78 118 yes no female 69 145 2
78 76 no no male 72 180 3
78 78 no no female 67 115 2
78 80 no no female 68 133 1
80 96 yes no male 72 155 2
80 128 yes no female 68 125 2
80 74 no no female 64 102 2
82 100 yes no female 68 138 2
82 84 no yes male 73 180 2
82 80 no no female 63 116 1
84 84 yes no male 72 150 3
84 84 no no male 69 136 2
84 84 no no female 66 130 2
84 80 no no female 65 118 1
86 84 no no female 67 150 3
87 84 no no female 63 95 3
88 110 yes yes female 69 150 2
88 84 no no male 73.5 155 2
88 74 no yes female 65 135 2
90 94 yes yes male 74 160 1
90 88 no yes male 67 140 2
90 90 no no male 68 145 1
90 92 no yes female 64 125 1
92 84 yes yes male 70 153 3
92 94 no yes male 69 150 2
94 92 no yes female 62 131 2
96 140 yes no female 61 140 2
96 116 yes no female 68 116 2
100 115 yes yes female 63 121 2

Solutions

Expert Solution

Test for Equal Variances

The hypothesis being tested is:

Null hypothesis All variances are equal
Alternative hypothesis At least one variance is different
Significance level α = 0.05

95% Bonferroni Confidence Intervals for Standard Deviations

ActivityL N StDev CI
1 10 14.0412 (8.94479, 29.8808)
2 61 10.9847 (9.00209, 13.9979)
3 21 9.6259 (6.96360, 15.1913)

Individual confidence level = 98.3333%

Tests

Method Test
Statistic
P-Value
Bartlett 1.87 0.393

The p-value is 0.393.

Since the p-value (0.393) is greater than the significance level (0.05), we fail to reject the null hypothesis.

Therefore, we cannot conclude that all variances are equal.

Analysis of Variance

The hypothesis being tested is:

Null hypothesis All means are equal
Alternative hypothesis Not all means are equal
Significance level α = 0.05
Factor Levels Values
ActivityL 3 1, 2, 3

Analysis of Variance

Source DF Adj SS Adj MS F-Value P-Value
ActivityL 2 161.1 80.54 0.66 0.520
Error 89 10867.3 122.11
Total 91 11028.4

The p-value is 0.520.

Since the p-value (0.520) is greater than the significance level (0.05), we fail to reject the null hypothesis.

Therefore, we can conclude that all means are equal.


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