In: Statistics and Probability
The U-Drive Rent-A-Truck company plans to spend $8 million in 280 new vehicles. Each commercial van will cost $25,000, each small truck 30,000, and each large truck 40,000. Past experience shows that they need twice as many vans as small trucks. How many of each type of vehicle can they buy?
solution:
we will use the equation system to solve this problem
explanation step by step:
There are three types of vehicles, and it is said that the number of vans is twice the number of small trucks.
let t denots the truck , S denote the small truck
and van = 2S....(because vans are twice than small truck)
total vehicle plans to buy = 280
we can formulate the equation as
T + S + 2S = 280
T + 3S = 280.............equation i
the company plans to spend $ 8 million on these vhicles
the cost of each vehicle is given by
van cost =$25000, small truck cost = $30,000 and large truck =$40,000
so formulate the second equation we get
40,000T + 30,000S + 25,000(2S) = 8,000,000
by solving this equation we get
40,000T + 80,000S = 8,000,000...............equation ii)
from equi i we get
T = 280-3s
putting value of t in equitaion 11
we get ,
40,000(280-3S) + 80,000 S = 8,000,000
by solving equation we get
S = 80
putting value of s in equation i we get
T = 280-3(80)
T = 40
so number of vehicle to purchase are
so number of van = 2*80 = 160
small truck = 80
large truck = 40