In: Statistics and Probability
An insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 92 of them. Construct the 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.
Question: 95% CI= (___%,___%) (round to one decimal place as needed.)
Sample proportion = 92 / 559
= 0.165
95% confidence interval for p is
-
Z
/2 * sqrt [
(1 -
) / n ] <
p <
+
Z
/2 * sqrt [
(1 -
) / n ]
0.165 - 1.96 * sqrt [ 0.165 * ( 1 - 0.165 ) / 559] < p < 0.165 + 1.96 * sqrt [ 0.165 * ( 1 - 0.165 ) / 559]
0.134 < p < 0.196
95% CI is (13.4% , 19.6% )