Three players toss coins simultaneously. For each player, P (H) = p, P (T) = q....

Three players toss coins simultaneously. For each player, P (H) = p, P (T) = q. If the result is 2H and 1T or the result is 2T and 1H, then the player that is different from the other two is called the odd man out and the game is over. If the result is 3H or 3T, then the players toss again until they get an odd man out. Find the probability that the game lasts at least 6 rounds.

Expert Solution

orchestra answered 2 years ago

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