Question

In: Computer Science

Employee_id First_name Last_name Salary Joining_date Department 1 John Abraham 1000000 01-JAN-13 12.00.00 AM Banking 2 Michael...

Employee_id

First_name

Last_name

Salary

Joining_date

Department

1

John

Abraham

1000000

01-JAN-13 12.00.00 AM

Banking

2

Michael

Clarke

800000

01-JAN-13 12.00.00 AM

Insurance

3

Roy

Thomas

700000

01-FEB-13 12.00.00 AM

Banking

4

Tom

Jose

600000

01-FEB-13 12.00.00 AM

Insurance

5

Jerry

Pinto

650000

01-FEB-13 12.00.00 AM

Insurance

6

Philip

Mathew

750000

01-JAN-13 12.00.00 AM

Services

7

TestName1

123

650000

01-JAN-13 12.00.00 AM

Services

8

TestName2

Lname%

600000

01-FEB-13 12.00.00 AM

Insurance

Write the following queries:

1. Get all employee details from the employee table

2.Get First_Name from employee table using alias name “Employee Name”, sorted descending

3.Get unique DEPARTMENT from employee table

4.Get employee details from employee table whose employee name are “John” and “Roy”

5.Get employee details from employee table whose employee name are not “John” and “Roy”

6.Get employee details from employee table whose first name contains 'o'

7.Get employee details from employee table whose first name ends with 'n'

8.Get employee details from employee table whose Salary between 500000 and 800000

9.Get employee details from employee table whose name is 'John' and 'Michael'

Solutions

Expert Solution

Ans:

1.select Employee_Id,First_name,Last_name,Joining_date,Department from employee;

2.select First_name as Employee Name from employee order by First_name desc;

3 select distinct Department from employee;

4.select Employee_Id,First_name,Last_name,Joining_date,Department from employee where First_name="John" or FIrst_name="Roy";

5.select Employee_Id,First_name,Last_name,Joining_date,Department from employee where First_name<>"John" and First_name<>"Roy";

6.select Employee_Id,First_name,Last_name,Joining_date,Department from employee where First_name like "%o%";

7.select Employee_Id,First_name,Last_name,Joining_date,Department from employee where First_name like "%n";

8.select Employee_Id,First_name,Last_name,Joining_date,Department from employee where Salary between 500000 and 800000;

9.select Employee_Id,First_name,Last_name,Joining_date,Department from employee where First_name="John" or First_name="Michael";


Related Solutions

Employee_id First_name Last_name Salary Joining_date Department 1 John Abraham 1000000 01-JAN-13 12.00.00 AM Banking 2 Michael...
Employee_id First_name Last_name Salary Joining_date Department 1 John Abraham 1000000 01-JAN-13 12.00.00 AM Banking 2 Michael Clarke 800000 01-JAN-13 12.00.00 AM Insurance 3 Roy Thomas 700000 01-FEB-13 12.00.00 AM Banking 4 Tom Jose 600000 01-FEB-13 12.00.00 AM Insurance 5 Jerry Pinto 650000 01-FEB-13 12.00.00 AM Insurance 6 Philip Mathew 750000 01-JAN-13 12.00.00 AM Services 7 TestName1 123 650000 01-JAN-13 12.00.00 AM Services 8 TestName2 Lname% 600000 01-FEB-13 12.00.00 AM Insurance And Table Name : Incentives Employee_ref_id Incentive_date Incentive_amount 1 01-FEB-13...
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