In: Statistics and Probability
A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 429.0 gram setting. It is believed that the machine is underfilling the bags. A 40 bag sample had a mean of 425.0 grams. A level of significance of 0.02 will be used. Determine the decision rule. Assume the standard deviation is known to be 11.0.
Enter the decision rule.
Solution:
Given:
We have to test if mean amount of weight is less than 429.0 gram or not.
thus hypothesis are:
Vs
Level of significance =
Sample size = n= 40
Population standard deviation is known and we have to determine the decision rule.
Since population standard deviation is known and sample size n is large, we use z distribution ( standard Normal distribution) to find decision rule.
Alternative hypothesis H1 is < type, thus this is two tailed test, hence we look for area 0.0200 in left tail of z table.
Look in z table for area = 0.0200 or its closest area and find corresponding z value.
Area 0.0202 is closest to 0.0200 and it corresponds to -2.0 and 0.05
thus z = -2.05
thus decision rule is:
Reject null hypothesis H0, if