Question

In: Statistics and Probability

Home sellers participating in a survey indicated that it typically took between 6 and 14 months...

Home sellers participating in a survey indicated that it typically took between 6 and 14 months to sell a house. Suppose that the distribution of the time that it took to sell a house could be approximated by a normal distribution with a mean of 10 months and a standard deviation of 4 months.

(a) What percent of the homes sold took less than 9 months to sell?

(b) What percent of the homes sold took between 10 and 16 months to sell?

(c) How long did it take for 70% of homes to sell?

(d) If 25 sold homes randomly selected, what is the probability that the mean selling time of is less than 9 months?

(e) Is either of the following less likely than the other? If so, which one and why? If not, why not?

(i) Randomly selecting a home that takes less than 9 months to sell

(ii) Finding a random sample of 25 homes with a mean selling time of less than 9 months.

Solutions

Expert Solution

(a)

Let T be the time taken to sell a house. Then T ~ Normal( = 10, = 4)

Percent of the homes sold took less than 9 months to sell = P(T < 9)

= P[Z < (9 - 10) / 4]

= P[Z < -0.25]

= 0.4013 = 40.13%

(b)

Percent of the homes sold took less than between 10 and 16 months to sell = P(10 < T < 16)

= P[T < 16] - P[T < 10]

= P[Z < (16 - 10) / 4] - P[Z < (10 - 10) / 4]

= P[Z < 1.5] - P[Z < 0]

= 0.9332 - 0.5

= 0.4332 = 43.32%

(c)

Let t be the time taken for 70% of homes to sell.

P[T < t] = 0.70

P[Z < (t - 10)/4] = 0.70

(t - 10) / 4 = 0.5244 (Using Z distribution table)

t = 10 + 4 * 0.5244 = 12.0976 months

(d)

Standard error of mean = 4 / = 0.8

Then, mean selling time ~ Normal( = 10, = 0.8)

p=Probability that the mean selling time of is less than 9 months = P( < 9)

= P[Z < (9 - 10) / 0.8]

= P[Z < -1.25]

= 0.1056 = 10.56%

(e)

Finding a random sample of 25 homes with a mean selling time of less than 9 months is less likely than the Randomly selecting a home that takes less than 9 months to sell, because the standard deviation of mean selling time (0.8) is less than that of the random selling time or, the variation of mean selling time is less than that for random selling time.


Related Solutions

In a recent​ survey, 145 of 457employees responded that they typically took work with them on...
In a recent​ survey, 145 of 457employees responded that they typically took work with them on vacation and 68 responded that there are unwritten and unspoken expectations that they stay connected. Complete parts​ (a) through​ (d) below. a. Construct a 95​%confidence interval estimate for the population proportion of employees who typically take work with them on vacation. ​(Round to four decimal places as​ needed.) b. Construct a 95​ confidence interval estimate for the population proportion of employees who said that...
Describe an action a regulatory agency took against a business in the past 6 months. Post...
Describe an action a regulatory agency took against a business in the past 6 months. Post a link to your source. Do you agree or disagree with the action? Explain your reasoning and support it with the materials from this week. Make sure you provide the link to the source and also make sure the company is in the US
5.      Investment advisers typically advise emergency fund of 6 months salary reserves as appropriate to meet...
5.      Investment advisers typically advise emergency fund of 6 months salary reserves as appropriate to meet contingency need against unpredictable disruption. You are currently living pay check to paycheck, provide a solution to mitigate these uncertainties by ensuring sufficient liquidity. (300 words)
You purchased your home 6 years ago. At this time, you took out a mortgage for...
You purchased your home 6 years ago. At this time, you took out a mortgage for $200,000, for 30 years, with a fixed rate of 5%. You have made all payments on time but have paid nothing extra on the mortgage. Suppose you sell the house for $210,000 and pay a 6% commission. How much money will you receive (or have to pay) after you pay off your loan? Solve using a financial calculator.
14. Find the indicated area under the standard normal curve. Between zequals0 and zequals0.24 Click here...
14. Find the indicated area under the standard normal curve. Between zequals0 and zequals0.24 Click here to view page 1 of the standard normal table. LOADING... Click here to view page 2 of the standard normal table. LOADING... The area between zequals0 and zequals0.24 under the standard normal curve is nothing. ​(Round to four decimal places as​ needed.)
NUR219 MRSA A nursing home resident K.W., had a hip replacement 6 months ago and consequently...
NUR219 MRSA A nursing home resident K.W., had a hip replacement 6 months ago and consequently developed an infection with methicillin resistant Staphylococcus aureus and then osteomyelitis. He has a history of diabetes. Medication Questions K.W. receives vancomycin IVPB ordered at 15 mg/kg/day. K.W. weighs 220 lb. What daily dose would the patient receive? What nursing considerations are essential when giving this medication? What are the signs and symptoms and treatment the nurse would be alert for if K.W. developed...
Lucy gets home at a random time between 5:27 and 6:32 each evening, and watches the...
Lucy gets home at a random time between 5:27 and 6:32 each evening, and watches the next news show that’s on. Network 1 airs news shows every half-hour (at 5:00, 5:30, 6:00, etc.); network 2 airs news shows at 5 minutes past each half-hour. Lucy will not start watching a show that’s already in progress. (a) Let Ni be the event that Lucy ends up watching the news on network # i tomorrow, for i ∈ {1, 2}. Find P(Ni)....
With the area between the graphs: x+y=14 x+6=y^2 Find the area two different ways First way:...
With the area between the graphs: x+y=14 x+6=y^2 Find the area two different ways First way: [a,b]integral(f(x))dx + [b,c]integral(g(x))dx = whats is a,b,c, f(x), and g(x): Second way: [a, b]integral(h(y))dy what is a, b, and h(y)
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT