In: Statistics and Probability
Using the following data...
(a) Fill in the table:
X | Y | X2 | Y2 | XY |
8 | 5 | |||
4 | 3 | |||
9 | 7 | |||
7 | 6 | |||
5 | 6 | |||
ΣX = | ΣY = | ΣX2 = | ΣY2 = | ΣXY = |
(b) Compute the degrees of freedom and determine the critical value
of r for α = 0.05 (two-tails).
df =
r-critical =
(c) Compute SSX, SSY,
SP, and the Pearson correlation (r). (Use 3
decimals)
SSX =
SSY =
SP =
r =
(d) What decision should be made?
Retain the null.Reject the null.
(e) Calculate r2, the percentage of variance
explained: (Use 3 decimals)
r2 =
a)
x | y | x2 | y2 | xy | |
8 | 5 | 64 | 25 | 40 | |
4 | 3 | 16 | 9 | 12 | |
9 | 7 | 81 | 49 | 63 | |
7 | 6 | 49 | 36 | 42 | |
5 | 6 | 25 | 36 | 30 | |
Total | 33 | 27 | 235 | 155 | 187 |
b)
Degrees of freedom = n - 2 = 5 -2 = 3
α = 0.05 (two-tails)
From the Pearson correlation table, the critical value for α = 0.05 (two-tails) and df =3 is 0.878
i.e df = 3
r-critical = 0.878
c)
Now
d)
Decision rule:
If the computed r value is greater than the r tabular value, reject H0.
In our problem,
Computed value of r = 0.700
Tabulated value of r (r- critical ) = 0.878
Sincde the computed value of r is less than r-critical, there is no enough evidence to reject H0.
So, we fail to reject H0.
Decision: Retain the null
e)
Here,
r = 0.700
So,
r2 = ( 0.700)2 = 0.490
the percentage of variance explained = 49%