In: Finance
Acme Inc. owns a delivery truck worth $95,000. The truck is subject to the risk of physical damage, with the following loss probability distribution:
Annual Losses |
Probability |
$0 |
.85 |
$10,000 |
.10 |
$95,000 |
.05 |
Acme’s risk manager is considering three risk management options to manage this risk:
Loss Matrix
For retention, the loss is equal to the damage
For Full Insurance, the maximum loss is premium i.e 3500
For deductible insurance, the loss is premium i.e 2200 upto the deductible amount of 1000. Above deductible amount, it is Deductible+premium i.e 2200+1000= 3200
State of the World | |||
---|---|---|---|
Risk Management | Zero Loss | Loss of $10,000 | Loss of $95000 |
Full Insurance | 3500 | 3500 | 3500 |
Deductible Insurance | 2200 | 3200 | 3200 |
Retention | 0 | 10000 | 95000 |
Expected Loss= Probability*Loss Amount
a) Full Insurance Expected Loss= (0.85*3500)+(0.1*3500)+(0.05*3500) = 3500
b) Deductible Insurance Expected Loss= (0.85*2200)+(0.1*3200)+(0.05*3200) = 2350
c) Retention Expected Loss= (0.85*0)+(0.1*10000)+(0.05*95000) = 5750
The manager aims to minimise expected Loss. That is why he should choose Deductible Insurance as it has the lease expected loss out of available 3 options
Total Cost= Monetary Cost(Expected Cost)+ Worry Value
a) Full Insurance Total Cost = 3500+0 = 3500 (worry value for full insurance is zero)
b) Deductible Insurance Expected Loss= 2350+1200 = 2550
c) Retention Expected Loss= 5750+1500 = 7250
The manager aims to minimise Total Cost. That is why he should choose Full Insurance as it has the lease Total Cost out of the 3 options.