Question

1. A fish hatchery manager estimates that on average fisherpersons catch 3.5 fish each fishing trip. A random sample of 10 fisherpersons showed they caught 3.9 fish per trip, with a standard deviation of 1.7 fish. Perform a test of hypothesis at a .10 alpha level to determine whether or not her claim is true. Use a two tailed test of hypothesis

Answer 1

Solution :

Given that ,

= 3.5

= 3.9

= 1.7

n = 10

The null and alternative hypothesis is ,

H₀ :   = 3.5

H_a :    3.5

This is the two tailed test .

Test statistic = z

= ( - ) / / n

= ( 3.9 - 3.5) / 1.7 / 10

= 0.74

The test statistic = 0.74

P value = 2 * P(Z > 0.74 ) = 1 - P (Z < 0.74 )

= 2 * 1 - 0.7704

= 2 * 0.2296

= 0.4592

P-value = 0.4592

= 0.10

0.4592 > 0.10

P-value >  

Fail to reject the null hypothesis .

There is not sufficient evidence to test the claim .