Question

In: Statistics and Probability

The lengths of time​ (in years) it took a random sample of 32 former smokers to...

The lengths of time​ (in years) it took a random sample of

32

former smokers to quit smoking permanently are listed. Assume the population standard deviation is

5.6

years. At

alpha=0.060.,

is there enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is

13

​years? Complete parts​ (a) through​ (e).

yea Complete parts​ (a) through​ (e).

20.520.5

12.712.7

12.112.1

19.219.2

10.210.2

11.311.3

10.110.1

14.814.8

18.218.2

10.310.3

12.112.1

7.47.4

9.49.4

17.317.3

22.222.2

14.914.9

21.721.7

21.221.2

7.47.4

15.215.2

8.98.9

13.913.9

17.117.1

19.419.4

13.213.2

14.814.8

15.215.2

9.59.5

16.416.4

21.621.6

19.319.3

12.312.3

​(a) Identify the claim and state the null hypothesis and alternative hypothesis.

Solutions

Expert Solution

given data and some necessary calculations are:-

sample size(n) = 32

population sd () = 5.6

sample mean be:-

here as the populations d is known and the sample size is =32 >30, we will do 1 sample Z test for mean.

hypothesis:-

our claim is the null hypothesis, that is the mean time it takes smokers to quit smoking permanently is 13 years.

test statistic be:-

p value be:-

[ in any blank cell of excel type =NORMSDIST(1.698) press enter ]

decision:-

p value = 0.0895 >0.06 (alpha)

so, we fail to reject the null hypothesis.

conclusion:-

there is not enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 13 years at 0.06 level of significance.

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