In: Statistics and Probability
The lengths of time (in years) it took a random sample of
32
former smokers to quit smoking permanently are listed. Assume the population standard deviation is
5.6
years. At
alpha=0.060.,
is there enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is
13
years? Complete parts (a) through (e).
yea Complete parts (a) through (e).
20.520.5 |
12.712.7 |
12.112.1 |
19.219.2 |
10.210.2 |
11.311.3 |
10.110.1 |
14.814.8 |
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18.218.2 |
10.310.3 |
12.112.1 |
7.47.4 |
9.49.4 |
17.317.3 |
22.222.2 |
14.914.9 |
|
21.721.7 |
21.221.2 |
7.47.4 |
15.215.2 |
8.98.9 |
13.913.9 |
17.117.1 |
19.419.4 |
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13.213.2 |
14.814.8 |
15.215.2 |
9.59.5 |
16.416.4 |
21.621.6 |
19.319.3 |
12.312.3 |
(a) Identify the claim and state the null hypothesis and alternative hypothesis.
given data and some necessary calculations are:-
sample size(n) = 32
population sd () = 5.6
sample mean be:-
here as the populations d is known and the sample size is =32 >30, we will do 1 sample Z test for mean.
hypothesis:-
our claim is the null hypothesis, that is the mean time it takes smokers to quit smoking permanently is 13 years.
test statistic be:-
p value be:-
[ in any blank cell of excel type =NORMSDIST(1.698) press enter ]
decision:-
p value = 0.0895 >0.06 (alpha)
so, we fail to reject the null hypothesis.
conclusion:-
there is not enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 13 years at 0.06 level of significance.
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