Question

In: Biology

In a population of cats, the phenotypic frequency of black cats is 75 %, and the...

In a population of cats, the phenotypic frequency of black cats is 75 %, and the phenotypic frequency of white cats q2 is 25%. Assuming that black (B) is dominant and white (b) is recessive, calculate the appropriate frequency for BB or  p2  genotype  following for a population in Hardy-Weinberg equilibrium.

A

25%

B

50%

C

75%

D

100%

E

10%

Solutions

Expert Solution

Answer: A. 25%

Hardy Weinberg equilibrium is p2 + 2pq + q2 =1

                            p2 is the frequency of BB (homozygous dominant genotype)

                     2pq is the frequency of Bb (heterozygous genotype)

                     q2 is the frequency of bb (homozygous recessive genotype)

given that q2 25%

So,   p2 + 2pq = 75%

According to the principle of Mendelian inheritance, offsprings of a monohybrid cross will result in a 3:1 ratio of phenotypes.

       Bb    X Bb         BB (black)     

                                       Bb (black)     

   Bb (black)     

       bb (white)

here white bb - 25%

          So,   BB - 25%

                  Bb - 50%

So, p2 is the frequency of BB (homozygous dominant genotype) - 25%

                     


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