In a population of cats, the phenotypic frequency of black cats is 75 %, and the...

In a population of cats, the phenotypic frequency of black cats is 75 %, and the phenotypic frequency of white cats q² is 25%. Assuming that black (B) is dominant and white (b) is recessive, calculate the appropriate frequency for BB or p² genotype following for a population in Hardy-Weinberg equilibrium.

	A	25%
	B	50%
	C	75%
	D	100%
	E	10%

Solutions

Expert Solution

Answer: A. 25%

Hardy Weinberg equilibrium is p² + 2pq + q² =1

p² is the frequency of BB (homozygous dominant genotype)

2pq is the frequency of Bb (heterozygous genotype)

q² is the frequency of bb (homozygous recessive genotype)

given that q² 25%

So, p² + 2pq = 75%

According to the principle of Mendelian inheritance, offsprings of a monohybrid cross will result in a 3:1 ratio of phenotypes.

Bb X Bb BB (black)

Bb (black)

bb (white)

here white bb - 25%

So, BB - 25%

Bb - 50%

So, p² is the frequency of BB (homozygous dominant genotype) - 25%

gladiator answered 1 year ago

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