In: Statistics and Probability
Sales of People magazine are compared over a 5-week period at four Borders outlets in Chicago. |
Weekly Sales | |||
Store 1 | Store 2 | Store 3 | Store 4 |
103 | 95 | 87 | 100 |
105 | 73 | 89 | 117 |
106 | 79 | 74 | 88 |
115 | 78 | 106 | 101 |
114 | 99 | 94 | 100 |
Fill in the missing data. (Round your p-value to 4 decimal places, mean values to 1 decimal place, and other answers to 3 decimal places.) |
Treatment | Mean | n | Std. Dev |
Store 1 | |||
Store 2 | |||
Store 3 | |||
Store 4 | |||
One-Factor ANOVA | |||||
Source | SS | df | MS | F | p-value |
Treatment | |||||
Error | |||||
Total | |||||
(a) | You will need to run the One-Way ANOVA to test the following hypotheses: |
H0: μ1 = μ2 = μ3 = μ4 | |
H1: Not all the means are equal | |
α = 0.05 | |
|
(b) | Determine the value of F. (Round your answer to 2 decimal places.) |
F-value |
(c)Determine the p-value. (Round your answer to 4 decimal places.)
p-value
(d) |
On the basis of the above-determined values, choose the correct decision from below. |
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SSbetween = SStotal - SSwithin = 3346.55 - 1610.8
SSbetween = 1735.75
Based on above calculation following are answers for each questions
Analysis of Variance Summary Table
Source | Sum of Squares | Degrees of Freedom (df) | Mean Square | F test value | P-value |
Between | SSB = 1735.750 | k - 1 = 3 | MSB = 578.583 | F = 5.747 | 0.0073 |
Within (error) | SSW = 1610.8 | N - k = 16 | MSW = 100.675 | ||
Total | 3346.550 | 19 |
F-value = 5.75
P-value = 0.0073 (Obtained using online calculator for F(3,16) = 5.747. Screenshot attached)
Since p-value = 0.0073 < α = 0.05, reject the null hypothesis.