Question
In: Statistics and Probability
A survey found that women's heights are normally distributed with mean 63.9 in. and standard deviation...
A survey found that women's heights are normally distributed with mean 63.9 in. and standard deviation 3.4 in. The survey also found that men's heights are normally distributed with mean 68.9 in. and standard deviation 3.4 in. Consider an executive jet that seats six with a doorway height of 55.8 in. Complete parts (a) through (c) below.
The percentage of men who can fit without bending?___%
Does the door with design with a height of 55.8 in appear adequate?Why didn't the engineers design a large door?
What doorway height would allow 40% of men to fit without bending?
Solutions
Expert Solution
Precentage of men =
µ = 68.9
σ = 3.4
P( X ≤ 55.8 ) = P( (X-µ)/σ ≤ (55.8-68.9)
/3.4)
=P(Z ≤ -3.853 ) = 0.0000584
0.00584 %
b)
No it does not seems adequate.
A large door might impact the airplane design.
c)
µ= 68.9
σ = 3.4
proportion= 0.4
Z value at 0.4 =
-0.25 (excel formula =NORMSINV(
0.4 ) )
z=(x-µ)/σ
so, X=zσ+µ= -0.25 *
3.4 + 68.9
X = 68.04
(answer)
THANKS
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orchestra answered 2 years agoRelated Solutions
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