In: Economics
Two possible power line routes are under consideration. Find the equivalent uniform annual cost for each if the interest rate is 7%. Which route should be chosen?
| 
 Route A  | 
 Route B  | 
|
| 
 Length (km)  | 
 15  | 
 5  | 
| 
 First Cost ($/km)  | 
 $5,000  | 
 $25,000  | 
| 
 Annual Maintenance ($/km)  | 
 $200  | 
 $400  | 
| 
 Useful Life (years)  | 
 15  | 
 15  | 
| 
 Salvage Value ($/km)  | 
 $3,000  | 
 $5,000  | 
| 
 Yearly Power Loss ($/km)  | 
 $500  | 
 $500  | 
| 
 Annual Property Taxes  | 
 $100  | 
 $500  | 
Working notes:
(1) Annual maintenance = Length of power line x Maintenance per KM
Route A: 15 x $200 = $3,000
Route B: 5 x $400 = $2,000
(2) Annual power loss = Length of power line x Power loss per KM
Route A: 15 x $500 = $7,500
Route B: 5 x $500 = $2,500
(3) Annual Total cost = Annual maintenance + Annual power loss + Annual property tax
Route A ($): 3,000 + 7,500 + 100 = 10,600
Route B ($): 2,000 + 2,500 + 100 = 4,600
(4) Salvage value is deducted for EAC computation, since it is a cash inflow.
(5) EAC are computed as follows.
EAC, Route A ($) = 5,000 x A/P(7%, 15) + 10,600 - 3,000 x P/F(7%, 15) x A/P(7%, 15)
= 5,000 x 0.1098** + 10,600 - 3,000 x 0.3624** x 0.1098** = 549 + 10,600 - 394
= 10,755
EAC, Route B ($) = 25,000 x A/P(7%, 15) + 4,600 - 5,000 x P/F(7%, 15) x A/P(7%, 15)
= 25,000 x 0.1098** + 4,600 - 3,000 x 0.3624** x 0.1098** = 2,745 + 4,600 - 119
= 7,226
Since Route B has lower EAC, this should be chosen.
**From A/P and P/F Factor tables