In: Advanced Math
Find the equation of the ellipse with foci at (0, 0) and (2, 2), with eccentricity e = 0.5. Express the equation in standard form ax2 + by2 + cxy + dx + ey = f and in terms of the distance formula sqrt(x^2+y^2) + sqrt[(x-2)^2 +(y-2)^2]=?
There is an answer posted on Chegg, but I don't think I agree with it. Since the foci are at (0, 0) and (2, 2) it seems that the major axis is rotated 45 degrees CCW. I can find a, b, and c. I don't understand how to account for the rotation in the formula. Can you help?
poge) Guanthet foci We0,o) and2,2). 20antrely e o.s Lat at focus WWe Cantu ofelliese He at know f 2 6. t adt-ores C= (0 So Conta ) (1) 2-to dktomce om Co to toei Now dslomer ron enlex to fo Ae ellipse on be Qrd Cortlomt a bo foit dano hom of ottlomus elirde to foci
paye-2 Henas the eauahan g olinde 2a CPG-(2a-PA - 4a fe 4a+ PF 73 2-2 ) + () 25 4 a Kt -4-4y+8 32 + 32-&+41+4 8 - (2t4) av ( &3Lty)
page-3 th (-)+ (-I) 4t3 Cty+9 2 2- 2 (nty) 2 -442 2 Mple in he reurad eaf Slordovd fom