Sketch a graph of f(x)= -2(x-1)^2(x+1), based on all the data
about zeros, long run behavior,...
Sketch a graph of f(x)= -2(x-1)^2(x+1), based on all the data
about zeros, long run behavior, etc.
Solutions
Expert Solution
From the given equation of the function, we have discovered
several characteristcs of the function and accordingly, the graph
can be drawn. The complete computations are provided in the
attachments and the graph is also attached after that.
1. Sketch the graph of a function that has degree 3, and zeros
at -2, +2, and +3. Is there only one possible graph? Explain.
2. Find the equation of a 3rd degree function that
has a zero of order 3, a vertical stretch of -2, is translated 3
units to the right and 5 units up. (2,21) is a point on the
function.
Determine all significant features by hand and sketch the
graph
f(x)=x/x+2
Please provide all work needed to solve the problem with
explanations. Thank you!
Summarize the pertinent information obtained by applying the
graphing
strategy and sketch the graph of f(x)=-2x/(x-1)^2
Part 1: Find the x-intercepts of f(x). Select the correct
choice below and, if necessary, fill in the answer box to
complete your choice.
A.The x-intercept(s) is/are at x=____. (Type an integer or a
decimal. Use a comma to separate answers as needed.)
B. There are no x-intercepts.
Part 2. Find the y-intercepts of f(x). Select the correct
choice below and, if necessary, fill...
Sketch the graph of a function f(x) that satisfies all the given
conditions. Clearly label any asymptotes, extreme values and points
of inflection.
f(x) is only discontinuous at x = −4.
f(x) has a global minimum but no global maximum.
f'(x) > 0 only on the intervals (−∞, −4) and (1, 3).
f(x) only changes concavity at x = −1 and x = 4.
limx→∞ f(x) = 4.
For the following exercises, use the information about the graph of a polynomial function to determine the function. Assume the leading coefficient is 1 or −1. There may be more than one correct answer.The y-intercept is (0, −4). The x-intercepts are (−2, 0), (2, 0). Degree is 2. End behavior: as x → −∞, f(x) → ∞, as x → ∞, f(x) → ∞.
Let
f(x) = 14 −
2x.
(a)
Sketch the region R under the graph of f on
the interval
[0, 7].
The x y-coordinate plane is given. There is 1
line and a shaded region on the graph.
The line enters the window at y = 13 on the positive
y-axis, goes down and right, and exits the window at
x = 6.5 on the positive x-axis.
The region is below the line.
The x y-coordinate plane is given. There...
Find the real zeros of the function f(x) = -(x+1)^3(x-2)^2 and
their corresponding multiplicities. Use the information along with
a sign chart (diagram) and then the end behavior to provide a rough
sketch of the graph of the polynomial.
Sketch the graph of a single function f that satisfies
all of the conditions below.
(a) f '(x) < 0 on (1,∞),
f '(x) > 0 on (−∞,1)
(b) f ''(x) > 0 on (−∞,−2) and (2,∞),
f ''(x) < 0 on (−2,2)
(c) lim x→−∞ f(x) =
−2, lim x→∞ f(x) = 0