In: Statistics and Probability
Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sample data below show the number of companies providing health insurance for small, medium, and large companies. For the purposes of this study, small companies are companies that have fewer than employees. Medium-sized companies have to employees, and large companies have or more employees. The questionnaire sent to employees asked whether or not the employee had health insurance and then asked the enployee to indicate the size of the company.
Health Insurance | |||||
Size of Company | Yes | No | Total | ||
Small | 37 | 13 | 50 | ||
Medium | 62 | 13 | 75 | ||
Large | 90 | 10 | 100 |
a. Conduct a test of independence to determine whether health insurance coverage is independent of the size of the company. What is the P-value?
Compute the value of the X^2 test statistic (to 2 decimals).
The P-value is .025 and .05
Using .05 level of significance
b. A newspaper article indicated employees of small companies are more likely to lack health insurance coverage. Calculate the percentages of employees without health insurance based on company size (to the nearest whole number).
Small | |
Medium | |
Large |
a)
Applying chi square test of independence: |
Expected | Ei=row total*column total/grand total | yes | No | Total |
small | 42.0000 | 8.0000 | 50.00 | |
medium | 63.0000 | 12.0000 | 75.00 | |
large | 84.0000 | 16.0000 | 100.00 | |
total | 189.00 | 36.00 | 225.00 | |
chi square χ2 | =(Oi-Ei)2/Ei | yes | No | Total |
small | 0.595 | 3.125 | 3.7202 | |
medium | 0.016 | 0.083 | 0.0992 | |
large | 0.429 | 2.250 | 2.6786 | |
total | 1.0397 | 5.4583 | 6.498 | |
test statistic X2 = | 6.50 |
The P-value is between .025 and .05
b)
small | 26% |
medium | 17% |
large | 10% |
small companies have a higher percentage of no coverage than large and medium companies |