In: Statistics and Probability
Suppose we wish to analyze the proportion of people who purchase insurance for screen replacement on their cell phones. Out of a random sample of 70 cell phone owners, we find that 32 purchased screen replacement insurance. Calculate a 98% confidence interval for the true proportion of cell phone owners who purchase screen replacement insurance.
Solution:
We know that:
The 98% confidence interval for the true proportion of cell phone owners who purchase screen replacement insurance is:
Therefore, the 98% confidence interval for the true proportion of cell phone owners who purchase screen replacement insurance is: