In: Operations Management
During a recent period of high unemployment, hundreds of thousands of drivers dropped their automobile insurance. Sample data representative of the national automobile insurance coverage for individuals 18 years of age and older are shown here.
Automobile Insurance | |||
Yes | No | ||
Age | 18 to 34 | 1500 | 340 |
35 and over | 1900 | 260 |
a. Develop a joint probability table for these data and use the table to answer the remaining questions. If required, round your answers to three decimal places.
b.What do the marginal probabilities tell you about the age of the U.S. population?
c.What is the probability that a randomly selected individual does not have automobile insurance coverage? If required, round your answer to three decimal places.
d.If the individual is between the ages of 18 and 34, what is the probability that the individual does not have automobile insurance coverage? If required, round your answer to three decimal places.
e.If the individual is age 35 or over, what is the probability that the individual does not have automobile insurance coverage? If required, round your answer to three decimal places.
f.If the individual does not have automobile insurance, what is the probability that the individual is in the 18-34 age group? If required, round your answer to three decimal places.
g.What does the probability information tell you about automobile insurance coverage in the United States?
Automobile Insurance |
|||
Yes |
No |
||
Age |
18 to 34 |
1500 |
340 |
35 and over |
1900 |
260 |
Total number of drivers= 1500+340+1900+260=4000
Answer A:- A joint probability table will be formed as below:-
Automobile Insurance |
||||
Yes |
No |
|||
Age |
18 to 34 |
1500/4000 =0.375 |
340/4000=0.085 |
|
35 and over |
1900/4000=0.475 |
260/4000=0.065 |
||
Automobile Insurance |
||||
Yes (Y) |
No (N) |
Total |
||
Age |
18 to 34(A) |
0.375 |
0.085 |
0.46 |
35 and over (B) |
0.475 |
0.065 |
0.54 |
|
Total |
0.85 |
0.15 |
1 |
In the above table
P(A) =0.46
P(B)=0.54
P(Y)=0.85
P(N)=0.15
Where,
(A)= age group of 18-34
(B) = 35 and above
(Y)= Those who have insurance
(N)= Those who do not have insurance
Answer B:- In the table of question A, P(A)=0.46 while P(B)=0.54
This will indicate that in the population of the USA, the people of age grip 18-3 are 46%, while the population of 35 years or more is 54%.
Answer C:- the probability that a randomly selected individual does not have automobile insurance coverage is represented as P(N) which is equal to 0.15 thus the answer is 0.15.
Answer D:- If the individual is between the ages of 18 and 34, the probability that the individual does not have automobile insurance coverage is represented by 340/4000=0.085
So the answer is”= 0.085
Answer E:- If the individual is age 35 or over, the probability that the individual does not have automobile insurance coverage is 260/4000=0.065
So the answer is:- 0.065
Answer F:- If the individual does not have automobile insurance, the probability that the individual is in the 18-34 age group is 340/(340+260) =0.57
So that answer is:- 0.567
Answer G:- The probability information indicates that the probability of young drivers to have the insurance is quite less in comparison to the drivers falling in the age group of 35 years and more.