Question

#include <iostream>

using namespace std;

void count( int begin[], int end[] )

{

int index, current[4] = { begin[0], begin[1], begin[2], begin[3] };

add:

goto print;

carry:

if ( current[index] < end[index] - 1 ) {

current[index]++;

goto add;

}

else if ( index > 0 ) {

current[index] = begin[index];

index--;

goto carry;

}

else return;

print:

cout << current[0] << current[1] << current[2] << current[3] << endl;

index = 3;

goto carry;

}

int main( )

{

int begin[4] = { 0, 0, 0, 0 };

int end[4] = { 2, 3, 2, 4 };

count(begin, end);

return 0;

}

remove all goto and get the same output

please type code and explain the code. thank you.

Answer 1

If you have any problem with the code feel free to comment.

Program

#include <iostream>
using namespace std;

void count( int begin[], int end[] )
{
    int index, current[4] = { begin[0], begin[1], begin[2], begin[3] };

    //initial print
    cout << current[0] << current[1] << current[2] << current[3] << endl;
    index = 3;
    //infinite loop
    while(1)
    {
        //add condition
        if ( current[index] < end[index] - 1 )
        {
            current[index]++;
            cout << current[0] << current[1] << current[2] << current[3] << endl;
            index = 3;
        }
        //carry condition
        else if ( index > 0 )
        {
            current[index] = begin[index];
            index--;
        }
        //exit the loop
        else
            return;
    }
}

int main( )
{
    int begin[4] = { 0, 0, 0, 0 };
    int end[4] = { 2, 3, 2, 4 };

    count(begin, end);

    return 0;
}

Output