Question

In: Statistics and Probability

An article included data from a survey of 2658 hiring managers and human resource professionals. The...

An article included data from a survey of 2658 hiring managers and human resource professionals. The article noted that many employers are using social networks to screen job applicants and that this practice is becoming more common. Of the 2658 people who participated in the survey, 1100 indicated that they use social networking sites (such as Facebook, MySpace, and LinkedIn) to research job applicants. For the purposes of this exercise, assume that the sample is representative of hiring managers and human resource professionals.

(a)

Assuming that this sample is random/representative of the population, what other assumptions need to be true before we can create a confidence interval?

Yes, because

n ≥ 30

No, because the population distribution is not normal.    Yes, because

n ≥ 10

and

n(1−)≥ 10

No, because either

n < 10

or

n(1−) < 10

No, because

n < 30

Yes, because the population distribution is normal.

(b)

Construct a 95% confidence interval for the proportion of hiring managers and human resource professionals who use social networking sites to research job applicants. (Round your answers to three decimal places.)

   ,  

(c)

Interpret a 95% confidence interval for p, the proportion of all hiring managers and human resource professionals who use social networking sites to research job applicants

We are  % confident that the proportion of all hiring managers and human resource professionals who use  social networking sites to research job applicants is between  % and  %

(d)

Suppose that the researchers wanted to estimate the proportion of hiring managers and human resource professionals to within mean reaction time to within 1% (Round your answer up to the nearest whole number.)

n =

Solutions

Expert Solution

a) Yes, because and

b)

c) We are 95% confident that the proportion of all hiring managers and human resource professionals who use  social networking sites to research job applicants is between 39.5% and 43.3%

d) here the marginof error = ME =0.01

for 95% confidence critical Z value is 1.96

since the proportion is not known we will assume p = 0.5


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