Question

Total plasma volume is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced by the overall health and physical activity of an individual. Suppose that a random sample of 46 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that σ = 7.70 ml/kg for the distribution of blood plasma.

(a) Find a 99% confidence interval for the population mean blood plasma volume in male firefighters. What is the margin of error? (Round your answers to two decimal places.)

lower limit
upper limit
margin of error

(b) What conditions are necessary for your calculations? (Select all that apply.)

σ is known n is large the distribution of weights is uniform σ is unknown the distribution of weights is normal

(c) Interpret your results in the context of this problem.

1% of the intervals created using this method will contain the true average blood plasma volume in male firefighters. The probability that this interval contains the true average blood plasma volume in male firefighters is 0.01.     99% of the intervals created using this method will contain the true average blood plasma volume in male firefighters. The probability that this interval contains the true average blood plasma volume in male firefighters is 0.99.

(d) Find the sample size necessary for a 99% confidence level with maximal margin of error E = 2.70 for the mean plasma volume in male firefighters. (Round up to the nearest whole number.)
male firefighters

Answer 1

a)

population std dev , σ =   7.7000

Sample Size ,n = 46

Sample Mean,  x̅ =37.5000

Level of Significance , α = 0.01   

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z value=z α/2=2.5758            [Excel formula =NORMSINV(α/2) ]

  

Standard Error , SE =    σ/√n =7.700/ √46=1.1353

margin of error, E=Z*SE =2.5758*1.135=2.924

  

confidence interval is  

Interval Lower Limit = x̅ - E = 37.50-2.924=34.58

Interval Upper Limit = x̅ + E = 37.50-2.924=40.42

margin of error, E=Z*SE =2.5758*1.135=2.92

b)

σ is known

n is large or normal population

c)

99% of the intervals created using this method will contain the true average blood plasma volume in male firefighters.

d)

Standard Deviation ,σ = 7.7000     

sampling error        , E =2.7

Confidence Level   ,CL=99%

  

alpha     =1-CL           =1%

Z value = Zα/2            = 2.576[excel formula   =normsinv(α/2)]

  

Sample Size,n = (Z * σ / E )² = (2.576*7.7/2.7) ²   =54.0

  

  

So,Sample Size needed= 54