Question

In: Statistics and Probability

IN A SURVEY OF 368 REGISTERED VOTERS, 167 OF THEM WISHED TO SEE MAYOR WAFFLESKATE LOSE...

IN A SURVEY OF 368 REGISTERED VOTERS, 167 OF THEM WISHED TO SEE MAYOR WAFFLESKATE LOSE HER NEXT ELECTION. CONSTRUCT A 90% CONFIDENCE INTERVAL FOR THE PROPORTION OF REGISTERED VOTER WHO WANT TO SEE MAYOR WAFFLESKATE DEFEATED.

Expert Solution

Solution :

Given that,

n = 368

x = 167

Point estimate = sample proportion = = x / n = 167/368=0.454

1 - = 1-0.454 =0.546

At 90% confidence level

= 1 - 90%

= 1 - 0.90 =0.10

/2 = 0.05

Z/2 = Z0.05 = 1.645 ( Using z table )

Margin of error = E Z/2 * $\sqrt$ (( * (1 - )) / n)

= 1.645 * $\sqrt$ ((0.454*0.546) / 368)

E = 0.0427

A 90% confidence interval for population proportion p is ,

- E < p < + E

0.454- 0.0427< p < 0.454+ 0.0427

0.4113< p < 0.4967

The 90% confidence interval for the population proportion p is : 0.4113, 0.4967

orchestra answered 1 year ago

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