A mixture is made by combining 19.9 mL of 1.2×10−3 M KSCN, 8.5 mL of 8.1×10−2...

A mixture is made by combining 19.9 mL of 1.2×10−3 M KSCN, 8.5 mL of 8.1×10−2 M Fe(NO3)3, and 11 mL of 0.198 M HNO3. Calculate the concentration of Fe3+ in the solution.

Expert Solution

Answer. given concentration of ferric nitrate is 8.1x10^-2 M and volume is 8.5 ml.

first finding the mass of ferric ions in the given concentration

.mass of Fe⁺³ ions m=(molarity*volume*molar mass)/1000

m=(8.1x10^-2*8.5*55.85) /1000

m=3.85x10^-2 g/mol.

Now finding the concentration of ferric ions in the mixture.total volume of the mixture=8.5+11+19.9=39.4 ml.

molarity =(3.85x10^-2 x1000)/(55.85x39.4)=38.5/2200.49=0.02M

concentration of Fe⁺³=0.02 M

queen_honey_blossom answered 2 years ago

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