Question

In: Statistics and Probability

An advertisement for a popular supermarket chain claims that it has had consistently lower prices than...

An advertisement for a popular supermarket chain claims that it has had consistently lower prices than four other full-service supermarkets. As part of a survey conducted by an "independent market basket price-checking company," the average weekly total, based on the prices (in $) of approximately 95 items, is given for two different supermarket chains recorded during 4 consecutive weeks in a particular month.

Week Advertiser ($) Competitor ($)
1 254.21 256.02
2 240.63 255.65
3 231.99 255.20
4 234.22 261.08

(a) Is there a significant difference in the average prices for these two different supermarket chains? (Use α = 0.05. Round your answers to three decimal places.)

1-2. Null and alternative hypotheses:

H0: μd < 0 versus Ha: μd > 0

H0: μd = 0 versus Ha: μd ≠ 0    

H0: μd ≠ 0 versus Ha: μd = 0

H0: μd = 0 versus Ha: μd < 0

H0: μd = 0 versus Ha: μd > 0


3. Test statistic:  t =  

4. Rejection region: If the test is one-tailed, enter NONE for the unused region.

t >
t <


5. Conclusion:

H0 is rejected. There is sufficient evidence to indicate that the means are different.

H0 is not rejected. There is insufficient evidence to indicate that the means are different.    

H0 is not rejected. There is sufficient evidence to indicate that the means are different.

H0 is rejected. There is insufficient evidence to indicate that the means are different.


(b) What is the approximate p-value for the test conducted in part (a)?

p-value < 0.010

0.010 < p-value < 0.020    

0.020 < p-value < 0.050

0.050 < p-value < 0.100

0.100 < p-value < 0.200

p-value > 0.200


(c) Construct a 99% confidence interval for the difference in the average prices for the two supermarket chains. (Round your answers to two decimal places.)
$  to $  

Interpret this interval.

Since 0 falls in the confidence interval, there is sufficient evidence to indicate that the means are different.

Since 0 does not fall in the confidence interval, there is sufficient evidence to indicate that the means are different.    

Since 0 does not fall in the confidence interval, there is insufficient evidence to indicate that the means are different.

Since 0 falls in the confidence interval, there is insufficient evidence to indicate that the means are different.

Solutions

Expert Solution

a)H0: μd = 0 versus Ha: μd ≠ 0

3)

Test statistic:  t = -3.011

4)

t >3.182

t<-3.182

5

H0 is not rejected. There is insufficient evidence to indicate that the means are different.   

b)

0.050 < p-value < 0.100

c)

for 99% CI; and 3 degree of freedom, value of t=
therefore confidence interval= sample mean -/+ t*std error
margin of errror          =t*std error=             32.440
lower confidence limit                     = -49.16
upper confidence limit                    = 15.71

-49.16 to 16.71

Since 0 falls in the confidence interval, there is insufficient evidence to indicate that the means are different.


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