In: Statistics and Probability
Suppose a study reports that the average price for a gallon of
self-serve regular unleaded gasoline is $3.76. You believe that the
figure is higher in your area of the country. You decide to test
this claim for your part of the United States by randomly calling
gasoline stations. Your random survey of 25 stations produces the
following prices.
$3.87 | $3.89 | $3.76 | $3.80 | $3.97 |
3.80 | 3.83 | 3.79 | 3.80 | 3.84 |
3.76 | 3.67 | 3.87 | 3.69 | 3.95 |
3.75 | 3.83 | 3.74 | 3.65 | 3.95 |
3.81 | 3.74 | 3.74 | 3.67 | 3.70 |
Assume gasoline prices for a region are normally distributed. Do
the data you obtained provide enough evidence to reject the claim?
Use a 1% level of significance. (Round the intermediate
values to 2 decimal places. Round your answer to 2 decimal
places.)
The value of the test statistic is t =_____ and we fail to reject the null hypothesis. |
Ho : µ = 3.76
Ha : µ > 3.76 (Right tail
test)
Level of Significance , α =
0.010
sample std dev , s = √(Σ(X- x̅ )²/(n-1) )
= 0.0889
Sample Size , n = 25
Sample Mean, x̅ = ΣX/n =
3.7948
degree of freedom= DF=n-1=
24
Standard Error , SE = s/√n = 0.0889/√25=
0.0178
t-test statistic= (x̅ - µ )/SE =
(3.7948-3.76)/0.0178= 1.96
critical t value, t* =
2.4922 [Excel formula =t.inv(α/no. of tails,df) ]
p-Value = 0.0310 [Excel formula
=t.dist(t-stat,df) ]
Decision: p-value>α, Do not reject null
hypothesis
Conclusion: There is not enough evidence that true mean is higher
than 3.76
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