Question

A basketball player makes 39% of her shots from the free throw line. Suppose that each of her shots can be considered independent and that she throws 3 shots. Let X = the number of shots that he makes. What is the probability that she makes 2 shots?

Answer 1

Here, n = 3, p = 0.39, (1 - p) = 0.61 and x = 2
As per binomial distribution formula P(X = x) = nCx * p^x * (1 - p)^(n - x)

We need to calculate P(X = 2)
P(X = 2) = 3C2 * 0.39^2 * 0.61^1
P(X = 2) = 0.2783