A freight train consists of 2 engines at the front, followed by 37 rail cars. Both...

A freight train consists of 2 engines at the front, followed by 37 rail cars. Both the engines and rail cars have the same mass of 407,629 kilograms each. Each engine exerts the same force backward on the track to push the train forward. The total force of friction on the entire train is 841,978 N and is evenly distributed among all of the cars and engines. Even with this friction present, the train engines are able to accelerate the train at 0.049 meters/second2. What is the magnitude of the force in Newtons that each engine would need to exert on the train track?

Solutions

Expert Solution

genius_generous answered 2 years ago

Next > < Previous

Related Solutions

A freight train consists of 2 engines at the front, followed by 10 rail cars. Both...

A freight train consists of 2 engines at the front, followed by 10 rail cars. Both the engines and rail cars have the same mass of 772,571 kilograms each. Each engine exerts the same force backward on the track to push the train forward. The total force of friction on the entire train is 810,810 N and is evenly distributed among all of the cars and engines. Even with this friction present, the train engines are able to accelerate the...

A freight train consists of 3 engines at the front, followed by 23 rail cars. Both...

A freight train consists of 3 engines at the front, followed by 23 rail cars. Both the engines and rail cars have the same mass of 458,924 kilograms each. Each engine exerts the same force backward on the track to push the train forward. The total force of friction on the entire train is 796,329 Newtons and is evenly distributed among all of the cars and engines. Even with this friction present, the train engines are able to accelerate the...

A freight train consists of 4 engines at the front, followed by 27 rail cars. Both...

A freight train consists of 4 engines at the front, followed by 27 rail cars. Both the engines and rail cars have the same mass of 690,888 kilograms each. Each engine exerts the same force backward on the track to push the train forward. The total force of friction on the entire train is 513,241 Newtons and is evenly distributed among all of the cars and engines. Even with this friction present, the train engines are able to accelerate the...

A freight train consists of two 8.00 x 105 kg engines and 45 cars with average...

A freight train consists of two 8.00 x 105 kg engines and 45 cars with average masses of 5.50 x 105 kg. (a) Assuming the force of friction is 7.50 x 105 N, calculate the force each engine must exert to accelerate the train at 5.00 x 10-2 m/s2. (b) What is the magnitude of the force in the link coupling the 10th and 11th train cars?

A freight train consists of two 8.1 x 10^4kg engines and 45 cars with average masses...

A freight train consists of two 8.1 x 10^4kg engines and 45 cars with average masses of 5.75 x10^4 kg each. m=8.1x10^4kg m2=5.75x10^4kg f=7.25x10^5 N Part (a): What is the magnitude of the force that each engine must exert backward on the track to accelerate the train at a rate of 5.00x10^-2m/s^2 if the force of friction is 7.6x10^5N, assuming the engines exert identical forces? This is not a large frictional force for such a massive system. Rolling friction for...

Consider two safety features found on modern cars: rear-view backup cameras and front-impact avoidance systems. Both...

Consider two safety features found on modern cars: rear-view backup cameras and front-impact avoidance systems. Both save lives, but rear-view backup cameras largely save the lives of very young children while front-impact avoidance systems save the lives of older drivers. A. In a benefit-cost analysis, should these lives saved be values identically or differently? Explain why. B. Why is your answer from part A important for benefit cost analyses of social distancing measures meant to reduce deaths from COVID-19?

Subjects