In: Statistics and Probability
Scores of an IQ test have a bell-shaped distribution with a mean of
100100 and a standard deviation of1919.
Use the empirical rule to determine the following.
(a) What percentage of people has an IQ score between 6262 and138138?
(b) What percentage of people has an IQ score less than4343or greater than157157?
(c) What percentage of people has an IQ score greater than 138138?
Given:
Mean, = 100
Standard deviation, =19
Empirical value ( 68%, 95%, 99.7%) rule:
68% data values lies within One standard deviation of the mean
95% data values lies within Two standard deviation of the mean
99.7% data values lies within Three standard deviation of the mean
z- score formula : z = X- /
a) P(62 < X < 138):
Case 1:
Z = (62 - 100)/19 = -2
Case 2:
Z = (138 - 100)/19 =2
By Empirical Rule, 95 % of data falls within two standard deviations from the mean.
So P(62< X <138) = 95%
b) P(X < 43 OR X > 157):
Case 1:
For X < 43:
Z = (43 - 100)/19 =-3
Case 2:
For X > 157:
Z = (157 - 100)/19 = 3
By Emprical Rlule, 99.7 % of data falls within the three standard deviation from the mean.
Therefore, 100% - 99.7% = 0.3% of people has an IQ score less than 43 or greater than 157
c)
P(X>138):
z = (138 - 100)/20 = 2
By empirical rule, 95 % fall within two standard deviations.
Percentage of people having greater than 160 :
95/2 = 47.5%
P(X>138) = 50% - 47.5% =2.5%
Therefore 2.5% of people has an IQ score greater than 138.