A certain type of congenital deafness in humans is caused by a rare dominant allele. In...

A certain type of congenital deafness in humans is caused by a rare dominant allele. In a mating involving a deaf man and a deaf woman, could all their children have normal hearing?

a. Yes, because traits assort independently.

b. No, because children favor their parents.

c. No, because it is dominant. Children always get the dominant alleles.

d. Yes, assuming that the parents are heterozygotes.

e. Yes, because it must be recessive if it's rare.

Solutions

Expert Solution

If The parents are homozygous for the trait

Let The genotype of Deaf parents = AhA (Where Ah is the rare dominant allele resulting in the deafness)

Crossing the two deaf parents

AhA x AhA

Gametes -----------> Ah A Ah A

Offsprings --------> AhAh AhA AhA AA

(Deaf) (Deaf) (Deaf) (Normal)

It means that there could be a normal offspring if the parents are heterozygous for the trait.

However if one or both parents are homozygous for the trait, all offsprings will be deaf. It will be shown as:

AhAh x AhAh

Gametes -----------> Ah Ah Ah Ah

Offsprings --------> AhAh AhAh AhAh AhAh

(Deaf) (Deaf) (Deaf) (Deaf)

AhAh x AhA

Gametes -----------> Ah Ah Ah A

Offsprings --------> AhAh AhA AhAh AhA

(Deaf) (Deaf) (Deaf) (Deaf)

Therefore the option d is correct.

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gladiator answered 1 year ago

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