Question

Find the zeros of given function : y= (x+1)²(x-1)(x-2)

Answer 1

Given function is : y= (x+1)²(x-1)(x-2)

We can write this function as

  y=(x+1)(x+1)(x-1)(x-2)

To find the zeros of function we have to take

0= (x+1)(x+1)(x-1)(x-2)

So x+1= 0

     x= -1

Or  x+1= 0

      x= -1

Or  x-1= 0

      x= 1

Or  x-2= 0

      x= 2

Here , the values of x are zeros of function.

Since, 1 is zero of given function and occurs two times

Therefore, its multiplicity is 2.

So, zeros of the function are -1( multiplicity of 2 ) , 1, 2

 

 

 

 

The Answer is -1(multiplicity of 2), 1, 2