Be sure to answer all parts.
Find the pH of the equivalence point and the volume...
Be sure to answer all parts.
Find the pH of the equivalence point and the volume (mL) of
0.0707MKOH needed to reach the
equivalence point in the titration of 23.4 mL of 0.0390MHNO2.
Be sure to answer all
parts.
Find the pH during the titration of 20.00 mL of 0.1000 M
triethylamine, (CH3CH2)3N
(Kb = 5.2
×10−4), with 0.1000 M HCl
solution after the following additions of titrant.
(a) 15.00 mL:
pH =
(b) 20.50 mL:
pH =
(c) 26.00 mL:
pH =
Be sure to answer all parts.
Find the pH during the titration of 20.00 mL of 0.1000 M
triethylamine, (CH3CH2)3N
(
Kb = 5.2
×
10−4
)
,
with 0.1000 M HCl solution after the following
additions of titrant.
(a) 10.00 mL:
pH =
(b) 20.50 mL:
pH =
(c) 25.00 mL:
pH =
Find the pH at the equivalence point(s) and the volume (mL) of
0.125 M HCl needed to reach the point(s) in titrations of the
following. (See this table.) (a) 69.0 mL of 0.225 M NH3 volume to
reach equivalence point pH at equivalence point
Be sure to answer all parts. Calculate the volume in mL of a
solution required to provide the following:
(a) 2.24 g of sodium chloride from a 0.415 M solution ___mL
(b) 5.40 g of ethanol from a 4.20 M solution ___mL
(c) 8.30 g of acetic acid (CH3COOH) from a 0.900 M solution
___mL
Be sure to answer all parts.
Calculate the pH during the titration of 40.00 mL of 0.1000
M HCl with 0.1000 M NaOH solution after the
following additions of base:
(a) 20.00 mL
pH =
(b) 39.40 mL
pH =
(c) 52.00 mL
pH =
Be sure to answer all parts find the value of S . Report the
value with the appropriate sign.
(a) 3 NO2( g ) + H2O( l ) 2 HNO3( l ) + NO( g ) J/K
(b) N2( g ) + 3 F2( g ) 2 NF3( g ) J/K
(c) C6H12O6( s ) + 6 O2( g ) 6 CO2( g ) + 6 H2O( g ) J/K
Find the volume (mL) and the pH of 0.135 M HCl needed to reach
the equivalence point(s) in titrations of the following. (You need
to find the pH at the equivalence point, not the initial pH of the
solution.
(a) 50.8 mL of 0.272 M NH3
(b) 11.8 mL of 1.76 M CH3NH2
Calculate the pH at the halfway point and at the equivalence
point for each of the following titrations.
a. 100.0 ml of 0.50 M HC7H5O2 (Ka = 6-4x10^-5) titrated by 0.10
M NaOH
b. 100.0 ml of 0.50 M C2H5NH2 (Kb= 5.6x10^-4) titrated by 0.10 M
HNO3
c. 100.0 ml of 0.50 M HCL titrated by 0.15 M NaOH
Please solve everything and explain. I am struggling with the
math soplease be sure to show all work, clearly! Thank you