Question

In: Math

4x-2y-2z=2 -x-5y+2z=-8 4x-5y+z=11 Please make sure you show all steps numerically, becuse I want to be...

4x-2y-2z=2
-x-5y+2z=-8
4x-5y+z=11

Please make sure you show all steps numerically, becuse I want to be sure I know how to arrive at the same numbers.

Solutions

Expert Solution

4 -2 -2 2
-1 -5 2 -8
4 -5 1

11

multiply the 1st row by 1/4

1 -1 / 2 -1 / 2 1/ 2
-1 -5 2 -8
4 -5 1 11

add 1 times the 1st row to the 2nd row

1 -1 / 2 -1 / 2 1/ 2
0 -11 / 2 3 / 2 -15 / 2
4 -5 1 11

add -4 times the 1st row to the 3rd row

1 -1 / 2 -1 / 2 1 / 2
0 -11 / 2 3 / 2 -15 / 2
0 -3 3 9
multiply the 2nd row by -2/11
1 -1 / 2 -1 / 2 1 / 2
0 1 -3 / 11 15 /11
0 -3 3 9

add 3 times the 2nd row to the 3rd row

1 -1/ 2 -1 / 2 1 / 2
0 1 -3 / 11 15/ 11
0 0 24 /11 144 / 11

multiply the 3rd row by 11/24

1 -1/ 2 -1 / 2 1 / 2
0 1 -3 / 11 15 / 11
0 0 1 6

add 3/11 times the 3rd row to the 2nd row

1 -1 / 2 -1 / 2 1 / 2
0 1 0 3
0 0 1 6

add 1/2 times the 3rd row to the 1st row

1 -1 / 2 0 7 / 2
0 1 0 3
0 0 1 6

add 1/2 times the 2nd row to the 1st row

1 0 0 5
0 1 0 3
0 0 1 6

Hence

x = 5, y = 3, z = 6

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