A golf ball strikes a hard, smooth floor at an angle of 35.0 ° and, as...

A golf ball strikes a hard, smooth floor at an angle of 35.0 ° and, as the drawing shows, rebounds at the same angle. The mass of the ball is 0.0542 kg, and its speed is 41.0 m/s just before and after striking the floor. What is the magnitude of the impulse applied to the golf ball by the floor? (Hint: Note that only the vertical component of the ball's momentum changes during impact with the floor, and ignore the weight of the ball.)

Expert Solution

There is only change in vertical component of momentum but horizontal component remains same.

Concept used:

impulse = change in momentum

genius_generous answered 2 years ago

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