Question

In: Physics

Light with wavelength n= 650nm is incident on 2 slits, each with a width of 0.25...

Light with wavelength n= 650nm is incident on 2 slits, each with a width of 0.25 mm and separated by 0.75 mm

a. What is the angle between the 2 first order minima on each side of the maximum created by the single slit pattern?
b. What is the distance from the central maximum to the first order maximum created by the double slits if the screen is 1.2 m away?

Expert Solution

Given the wavelength of the light = 650nm = 650 x 10-9m, width of the slit w = 0.25mm = 0.25 x 10-3m and the seperation of the slits d = 0.75mm = 0.75 x 10-3m.

a) The pattern formed by a single slit is the diffraction pattern. For diffraction pattern, the angular position of the nth minima from the centre is given by,

For first order minima n = 1. Therefore,

The angle between the 2 first order minima on each side of the maximum is

So the angle between the 2 first order minima on each side of the maximum is 0.0052.

b) The pattern created by the double slits is an interference pattern. Given the distance from the slit and screen is D = 1.2m. For interference pattern, the distance of central maximum to the nth order maximum is

For first order n = 1. Therefore,

So the distance of central maximum to the first order maximum is 1.04mm.

genius_generous answered 2 years ago

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