A 56.0-Ω resistor is connected in parallel with a 121.0-Ω resistor. This parallel group is connected...

A 56.0-Ω resistor is connected in parallel with a 121.0-Ω resistor. This parallel group is connected in series with a 22.0-Ω resistor. The total combination is connected across a 15.0-V battery.

(a) Find the current in the 121.0-Ω resistor. A

(b) Find the power dissipated in the 121.0-Ω resistor. W

Expert Solution

(b) Power dissipated across 121 = Voltage across 121 * Current through 121 = V * I1

Voltage across 121 = Current through 121 * resistance = I1 * 121 = 0.171 * 121 = 20.67 V

Power dissipated across 121 = V * I1 = 20.67 * 0.171 = 3.54 W

genius_generous answered 2 years ago

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