Question

In: Statistics and Probability

A statistical analyst for the Wall Street Journal randomly selected six companies and recorded both the...

A statistical analyst for the Wall Street Journal randomly selected six companies and recorded both the price per share of stock on January 1, 2009 and on April 30, 2009. The results are presented below. Suppose the analyst wished to see if the average price per share of stock on April 30, 2009 is less than the average price per share of stock on January 1, 2009 at α=.025.

Apr. 30, 2009   33   27   32   25   35   34
Jan. 1, 2009   40   28   30   34   48   36

For the hypothesis stated above, what is the P-value?

Solutions

Expert Solution

The p-value is:

The test:

For the score differences we have, mean is Dˉ=-5, the sample standard deviation is sD=5.6214, and the sample size is n=6.

(1) Null and Alternative Hypotheses
The following null and alternative hypotheses need to be tested:
Ho: μD =0
Ha: μD <0
This corresponds to a Left-tailed test, for which a t-test for two paired samples be used.

(2a) Critical Value
Based on the information provided, the significance level is α=0.025, and the degree of freedom is n-1=6-1=5. Therefore the critical value for this Left-tailed test is tc​=-2.5706. This can be found by either using excel or the t distribution table.

(2b) Rejection Region
The rejection region for this Left-tailed test is t<-2.5706

(3)Test Statistics
The t-statistic is computed as follows:


(4) The p-value
The p-value is the probability of obtaining sample results as extreme or more extreme than the sample results obtained, under the assumption that the null hypothesis is true. In this case,
the p-value is 0.0406

(5) The Decision about the null hypothesis
(a) Using traditional method
Since it is observed that t=-2.1787 > tc​=-2.5706, it is then concluded that the null hypothesis is Not rejected.

(b) Using p-value method
Using the P-value approach: The p-value is p=0.0406, and since p=0.0406>0.025, it is concluded that the null hypothesis is Not rejected.

(6) Conclusion
It is concluded that the null hypothesis Ho is Not rejected. Therefore, there is Not enough evidence to claim that the population mean μ1​ is less than μ2, at the 0.025 significance level.

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