Question

The gamma ray was fired with a Mev 7 energy, and it fell on a lead barrier and stopped inside it behind the barrier. There was a gamma ray spectrometer. As a result of this interaction, the spectrometer did not record the 7 Mev energy, but recorded a photovoltaic energy worth Kev 511. From these data, answer the questions.
A- What is the interaction between the photon and the lead barrier?
B- What are the particles resulting from this reaction and what are their energies?
C- If the photon of the KeV 511 energy shed falls on a barrier of the bees, then what is the energy of the orbital electron K that will be released as a result of energy absorption Kev 511 if you know that this electron is connected to a energy of KeV 8.98
D- If the photon with the energy Kev 511 is dispersed through an angle of 45 then how much will it be The dispersed powers of energy?

Answer 1

Ans(a)

Gamma rays are forms of electromagnetic radiation that occur with higher energy levels than those displayed by ultraviolet or visible light. Lead barriers are excellent for imaging procedures using ionizing radiation such as fluoroscopy, x-ray, mammography and CT.Gamma rays can pass through any thickness of material. The exponential expression e–Σz as used to describe neutron behavior can be carried over to the attenuation of gamma rays in matter. However, the photon coefficients are tabulated in terms of μ/ρ as the mass attenuation coefficient because ρ is the material density. Therefore, the unattenuated photon flux as a function of depth x into the material is described by

Ans (b)

The total gamma ray cross section curve for lead (Pb), as the sum of the components for Compton effect, photoelectric effect, and pair production, exhibits a minimum at approximately 3 MeV energy. This implies that gamma rays in this vicinity are more penetrating than those of higher or lower energy.

Ans (c)

The heavy element lead(Z=82) has K,Land M (principal quantum numbers,n=1,2,and 3)

binding energies of approximately 88, 15, and 3keV,respectively,which provide strong photoelectric absorption for photons in this energy region.

Ans (d) The dispersed power of energy