Calculate the absolute hardness, η, values for Pt2+, Cr2+, SO2, and PF3. Which Lewis acid/base is...

Calculate the absolute hardness, η, values for Pt2+, Cr2+, SO2, and PF3. Which Lewis acid/base is harder than the other? I = ionization energy; EA = electron affinity I (Pt2+) = 35.2 eV, EA (Pt2+) = 19.2 eV I (Cr2+) = 30.96 eV, EA (Cr2+) = 16.5 eV I (SO2) = 12.3 eV, EA (SO2) = 1.1 eV I (PF3) = 12.3 eV, EA (PF3) = - 1.0 eV

Solutions

Expert Solution

let absolute hardness of Pt2+ : 1, Cr2+:2, SO2:3 and PF3: 4

1 = 1/2(I -EA)

= 1/2(35.2 - 19.2)

= 8

2 = 1/2(30.96 - 16.5)

= 7.23

3 = 1/2(12.3 - 1.1)

= 5.6

4 = 1/2[12.3 - (- 1.0)]

= 1/2(12.3 + 1.0)

= 6.65

therefore; 12 4 3

gladiator answered 1 year ago

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