In: Physics
A baseball is hit with a horizontal speed of 16 m/s and a vertical speed of 12 m/s upward. What are these speeds 4 s later?
horizontal speed | m/s |
vertical speed | m/s |
Part A.
Initial horizontal speed = 16 m/sec
Since there is no acceleration in horizontal direction, So horizontal velocity remains constant, So
after 4 sec,
Vx = V0x = 16 m/sec
Part B.
Initial Vertical speed = 12 m/sec
In vertical direction there is acceleration due to gravity in downward direction, So a = -g = -9.81 m/sec^2
Using 1st kinematic equation:
V1y = V0y + a*t
V1y = 12 + (-9.81)*4
V1y = -27.24 m/sec