Question

Plot the function y = 10(1 = e-x/4) over the interval 0 ≤ x ≤ xmax, using a while loop to determine the value of xmax such that y(xmax) = 9.8.

Properly label the plot. The variable y represents force in newtons, and the variable x represents time in seconds.

Answer 1

x = 0;

x_max = 0;

% infinite loop

while true

   

    % calculate y

    y = 10 *\r\n( 1 - exp(\r\n-x / 4 )\r\n);

   

    % is the current value of x is the required xmax

    if y >= 9.8

       

        x_max = x;

        break;

       

    end

   

    x = x + 0.01;

   

end

% create a vector x

x =\r\n[ 0 : 0.01 : x_max ];

% create a vector y

y = 10 .*\r\n( 1 - exp(\r\n-x ./ 4 )\r\n);

% set the title of the axis

title(\'Plot y = 10( 1 - exp(-x / 4) )\');

% set the label of the axis

xlabel(\'x\');

ylabel(\'y\');

grid on

hold

% plot the graph

plot( x , y );

 

Output:-

x = 0;

x_max = 0;

% infinite loop

while true