In: Chemistry
Consider the reacton of bromine and chlorine gas to form BrCl where Kp=1.11X10^-4 at 150K. A reaction mixture initially contains a bromine partial pressure of 755 torr and a chlorine partial pressure of 735torr at 150K. Calculate the equilibrium partial pressure of BrCl at 25oC
Br2 + Cl2 -----------> 2BrCl
I 755 735 0
C -x -x 2x
E 755-x 735-x 2x
kp = P2BrCl/PBr2 PCl2
1.11*10-4 = (2x)2/(755-x)(735-x)
1.11*10-4 *(755-x)(735-x) = 4x2
x = 3.9
[BrCl] = 2x = 2*3.9 = 7.8torr