In: Chemistry
boiling point elevation of a solution containing 2.94 g sodium chloride and 114 g water
NaCl , i value = 2
mass of NaCl = 2.94 g
molar mass of NaCl = 58.5
moles of NaCl = mass / molar mass
= 2.94 / 58.5
= 0.0503
mass of water = 114 g = 0.114 kg
molality = moles / mass of solvent
= 0.0503 / 0.114
= 0.441 m
Kb of water = 0.512 oC / m
water boiling point To = 100 oC
Tb = i x Kb x m
= 2 x 0.512 x 0.441
= 0.451 oC
boiling point elevation = 0.451 oC
this means water boiling point increases from 100 oC to 100.451 oC