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In: Math

A tug of war has teachers and the principal challenging the students! In the first round...

A tug of war has teachers and the principal challenging the students! In the first round 3 teachers and 5 students came to a draw. In the second round the principal joined the students. The principal and 10 students came to a draw against 8 teachers in the second round. Assuming each teacher has the same strength, and each student has the same strength, who will win the tie breaking round if it is: 15 students and the principal challenging 10 teachers? Show your thinking.

Solutions

Expert Solution

In the first round 3 teachers and 5 students came to a draw. Hence, the strength of a student is 3/5th of the strength of a teacher.

In the second round, the principal and 10 students came to a draw against 8 teachers. The strength of 10 students is equal to the strength of (3/5)*10 = 6 teachers . Hence, the strengths of 6 teachers and the principal is equal to the strength of 8 teachers so that the strength of the principal is equal to the strength of 2 teachers.

Now, in the tie breaking round, 15 students and the principal are challenging 10 teachers. The strength of 15 students equals the strength of (3/5)*15 = 9 teachers and the strength of the principal is equal to the strength of 2 teachers. Therefore, the strengths of 15 students and the principal is equal to the strength of 11 teachers. Since they are challenging 10 teachers, hence, 15 students and the principal will win the tug of war.

milcah answered 2 years ago
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