Question

(1 point) Among drivers who have had a car crash in the last year, 220 were randomly selected and categorized by age, with the results listed in the table below.

Age	Under 25	25-44	45-64	Over 64
Drivers	88	51	31	50

If all ages have the same crash rate, we would expect (because of the age distribution of licensed drivers) the given categories to have 16%, 44%, 27%, 13% of the subjects, respectively. At the 0.05 significance level, test the claim that the distribution of crashes conforms to the distribution of ages. Keep at least two decimal places in your calculations.
The test statistic is ?2=χ2=  
The critical value is ?2=χ2=  
The conclusion is
A. There is sufficient evidence to warrant the rejection of the claim that the distribution of crashes conforms to the distibuion of ages.
B. There is not sufficient evidence to warrant the rejection of the claim that the distribution of crashes conforms to the distibuion of ages.

Answer 1

Answer:

H0 : p(under 25) = 0.16 ; p (25 -44) = 0.44 ; P(45 - 64) = 0.27 ; P(over 64) = 0.13

Ha : Here the expected crash rate is not as the license distribuition.

Here

Total sample size = 220

df = n-1 =4-1 = 3

Expected values of licensed categories are

for Under 25 = 220* 0.16 = 35.2

for 25 -44 age group = 220 * 0.44 = 96.8

for 45 - 64 age group= 220* 0.27 = 59.4

for over 64 group = 220 * 0.13 = 28.6

Age	Drivers(o)	Expected(E)	(O -E)^2/E
Under 25	88	35.2	79.2
25-44	51	96.8	21.6698
45-64	31	59.4	13.5784
over 64	50	28.6	16.0123
Sum	220	220	130.4605

the test statistic X2 = 130.4605

for level of significance 0.05 df =3 Critical value = 7.815

p-value=0

ie, p-value is less than =0.05 hence we reject H0

conclusion :- There is not sufficient evidence to warrant the rejection of the claim that the distribution of crashes conforms to the distibuion of ages

Option B is Correct

NOTE:: I HOPE THIS ANSWER IS HELPFULL TO YOU......**PLEASE SUPPORT ME WITH YOUR RATING......

**PLEASE GIVE ME "LIKE".....ITS VERY IMPORTANT  FOR,ME......PLEASE SUPPORT ME .......THANK YOU